P^2+3=p(2p+1)+1

Solution for P^2+3=p(2p+1)+1 equation:

^2+3=P(2P+1)+1

We move all terms to the left:

^2+3-(P(2P+1)+1)=0

We add all the numbers together, and all the variables

-(P(2P+1)+1)=0


We calculate terms in parentheses: -(P(2P+1)+1), so:

P(2P+1)+1

We multiply parentheses

2P^2+P+1

Back to the equation:

-(2P^2+P+1)


We get rid of parentheses

-2P^2-P-1=0

We add all the numbers together, and all the variables

-2P^2-1P-1=0

a = -2; b = -1; c = -1;
Δ = b2-4ac
Δ = -12-4·(-2)·(-1)
Δ = -7
Delta is less than zero, so there is no solution for the equation